2007-10-14 18:14:30 · 5 answers · asked by sexyhooper55 1 in Science & Mathematics ➔ Mathematics
Find values of y:
x - y = 3
y = x - 3
- 2x + 2y = - 6
- x + y = - 3
y = x - 3
Value of x:
x - 3 = x - 3
0 = 0
There is nothing we could further from here. This problem has no solution.
2007-10-14 18:19:55 · answer #1 · answered by Jun Agruda 7 · 2⤊ 0⤋
solve for x in {1}
x = 3 + y
Substitute to {2}
-2(3 + y) + 2y = 6
-6 - 2y + 2y = 6
Your equation are not independent, so no solution can be found.
2007-10-15 01:27:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x-y=3
=> 2x - 2y = 6
=> - 2x + 2y = -6
which is the same as the second equation.
Thus, all values of x and y which satisfy the first equation also satisfy the second equation.
Hence, the solution set is
{(x, y) l x - y = 3, x and y belong to R }
2007-10-15 01:24:32 · answer #3 · answered by Madhukar 7 · 0⤊ 0⤋
-2x+2y=-6
Divide by -2:
x-y=3, which was your first equation. X and Y can be anything, as long as X is 3 bigger than Y. I think they might be chromosomes.
2007-10-15 01:28:05 · answer #4 · answered by David D 2 · 0⤊ 0⤋
The two equations are the same.
No solution.
2007-10-15 06:12:32 · answer #5 · answered by Como 7 · 0⤊ 0⤋