(1/y + 2) / (7/y - 2)
2007-10-14 17:39:07 · 9 answers · asked by Jay-j 2 in Science & Mathematics ➔ Mathematics
1/y + 2 = (1 + 2y)/y
7/y - 2 = (7 - 2y)/y
(1 + 2y)/(7 - 2y)
2007-10-14 17:43:17 · answer #1 · answered by duffy 4 · 0⤊ 0⤋
solve 1/y+2 first.
= 1+2y/y
solve 7/y-2
=7-2y/y
then, simplify them
=1+2y/7-2y
so, = 1/7 - y
2007-10-14 17:49:48 · answer #2 · answered by lost gal 3 · 0⤊ 0⤋
Reading this as:-
1 / (y + 2) / 7 / (y - 2)
[1 / (y + 2) ] [ (y - 2) / 7 ]
(1/7) (y - 2) / (y + 2)
2007-10-15 21:38:50 · answer #3 · answered by Como 7 · 0⤊ 0⤋
ok first simplify both numerator and denominator.
Numerator: (1/y) + 2 = (1 + 2y)/y
Denominator: (7/y) - 2 = (7 - 2y)/y
get reciprocal of denominator: y / ( 7 - 2y)
Multiply numenrator and reciprocal of denomintor:
{(1 + 2y)/y } * {y / ( 7 - 2y)} = (1 + 2y)/ (7- 2y)
2007-10-14 17:44:42 · answer #4 · answered by jen ol 3 · 1⤊ 0⤋
Multiply by y/y:
(1 + 2y) / (7 - 2y)
1/(7 - 2y) + 2y/(7 - 2y) excluding y = 0
2007-10-14 17:47:19 · answer #5 · answered by David D 2 · 0⤊ 0⤋
1+2y/7-2y
2007-10-14 17:51:23 · answer #6 · answered by niz 1 · 0⤊ 0⤋
= (1/y + 2) / (7/y - 2)
= ([1 + 2y] / y) / ([7 - 2y] / y)
= (1 + 2y) / (7 - 2y)
Answer: (1 + 2y) / (7 - 2y)
2007-10-14 18:08:38 · answer #7 · answered by Jun Agruda 7 · 2⤊ 0⤋
(1/y + 2) = ((1 +2y)/y)
(7/y - 2) = (7-2y)/y)
((1 +2y)/y) / (7-2y)/y) ------------ flip the bottom part and multiply
(1 +2y)/y * y/(7-2y)
y(1+2y) / y(7-2y) --------- y's cancel
(1+2y) / (7-2y)
2007-10-14 17:51:42 · answer #8 · answered by Anonymous · 0⤊ 0⤋
it relatively is complicated, yet its no longer complicated. .. (3 / 4y) - (2 / y) / (a million / y) + (3 / 2y) = (3 / 4y) - (2 / y) * (y / a million) + (3 / 2y) = (3 / 4y) - (2 / a million) + (3 *2 / 4y) = (3 / 4y) - 2 + (6 / 4y) = (3 + 6) / (4y) - 2 = 9 / (4y) - 2 = 9 / (4y) - 8y/(4y) = ( 9 - 8y ) /(4y)
2016-11-08 08:39:37 · answer #9 · answered by zeh 4 · 0⤊ 0⤋