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(8) / (b/w - w/b)

2007-10-14 17:36:51 · 4 answers · asked by Jay-j 2 in Science & Mathematics Mathematics

4 answers

= 8 / ([b/w] - [w/b])
= 8 / ([b^2/bw] - [w^2/bw])
= 8 / ([b^2 - w^2]/bw)
= 8 * bw/(b^2 - w^2)
= 8bw/(b^2 - w^2)

2007-10-14 23:54:02 · answer #1 · answered by Jun Agruda 7 · 2 0

8 w b / ( b ² - w ² )
8 w b / [ (b - w) (b + w) ]

2007-10-15 09:40:51 · answer #2 · answered by Como 7 · 0 0

8 / [ (b^2-w^2)/bw ]
= 8 bw /(b^2-w^2)

2007-10-15 00:41:52 · answer #3 · answered by CPUcate 6 · 0 0

(b^2 - w^2)/wb

2007-10-15 00:41:02 · answer #4 · answered by tootoot 3 · 0 0

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