is it possible to factor 2x^3-x^2-4x+3?

Question

please reply back asap

Answer 1

it is possible to factor
if you try x=1 then you get 0
so (x-1) is a factor

you can use synthetic division if you'd like and you would get:
(x-1)(2x^2+x-3)
you can go further by noticing that
2x^2 +x -3 = (2x+3)(x-1)
so the factors are:
(x-1)(x-1)(2x+3)
(x-1)^2 (2x+3)

Answer 2

Yes

2x^3 - x^2 - 4x + 3
(x - 1) ( 2x^2 + x - 3)
(x - 1) (2x + 3) (x - 1)
(x-1)^2 (2x + 3)

Answer 3

1 ] 2 -1 -4 3
2 1 -3
2 1 -3 0

(x-1)(2x^2 +x -3) = (x-1)(2x+3)(x-1)=(2x+3)(x-1)^2

Answer 4

Yes...have you used synthetic division?
(x - 1)(2x^2 + x -3) = (x - 1)(2x + 3)(x -1) = (x - 1)^2 (2x + 3)

Answer 5

f(x) = 2x^3 - x^2 - 4x + 3

f(1) = 2 - 1 - 4 + 3 = 0

so x=1 is a root

so (x-1) is a factor

divide the expression by x-1

x-1)2x^3-x^2-4x+3(2x^2
___2x^3-2x^2
___________________
______x^2-4x(x
______x^2-x
__________________
________-3x+3(-3
________-3x+3
________________
___________0

so the quotient is 2x^2+x - 3

factorize 2x^2 + x - 3

2x^2 -2x + 3x - 3

2x(x -1) + 3(x-1)

(x-1)(2x+3)

so the factors are

(x-1)(x-1)(2x+3)

Answer 6

Yes.

. = ( x - 1 )² ( 2x + 3 )

Answer 7

f(1) = 2 - 1 - 4 + 3
f(1) = 5 - 5
f(1) = 0
Thus x - 1 is a factor.
To find other factors, use synthetic division:-
1|2___- 1___- 4___3
|_____2____1___-3
|2____1___- 3___0

(x - 1) (2 x ² + x - 3)
(x - 1) (2 x + 3) (x - 1)
(x - 1) ² (2 x + 3)

Answer 8

the farthest i got was 2x^3 - (x - 3)(x - 1)