How do I do this algebra problem?

Question

I'm so frustrated with this!! How do I subtract this problem?

5 / 64 - z^2 - 4 / z^2 + 9z + 8

Answer 1

put some brackets in next time too hard to understand

but what you need to do is to have everything over the same denominator to do this times each fraction by the others denominator

5 / (64 - z^2) - 4 / (z^2 + 9z + 8)

5(z^2 + 9z + 8)/ ((64 - z^2)(z^2 + 9z + 8)) - 4(64 - z^2)/((64 - z^2)(z^2 + 9z + 8))

(5(z^2 + 9z + 8) - 4(64 - z^2)) /((64 - z^2)(z^2 + 9z + 8))

now expand and simplify if possible

(5z^2 + 45z + 40 - 256 + 4z^2) / (-x^4-9x^3+56x^2+576x+512)

9(x-3)(x+8) / (-x^4-9x^3+56x^2+576x+512)

Answer 2

first try getting all like terms together and then subtract them. If you have already tried that, try finding the lcd. Good luck i wish I cold be more help.

Answer 3

Try multiplying each term by z^2

Answer 4

5z^2/(64z^2)-64z^4/(64z^2)-256/(64z^2)+576z^3/(64z^2)+
512z^2/(64z^2)
= ( -64z^4-256 +576z^3+517z^2)/(64z^2)

Answer 5

too hard for me!