88x - 5y =39 and -8x + 3y = -1?

Answer 1

88x - 5y = 39
-8x + 3y = -1 <-----multiply by 11 so that it becomes

88x - 5y = 39
-88x + 33y = -11
28y = 28

so y = 1 and now plug this value in for any of the two original equations you have

-8x + 3(1) = -1
-8x + 3 = -1
-8x = -4
x=0.5

Answer 2

multiply the second equation by 11

So u get 11(-8x + 3y) = 11(-1)
-88x + 33y = -11

Now add the two equations:

88x - 88x - 5y + 33y = 39 - 11
28y = 28
y = 1

Plug the y value into an equation
-8x + 3(1) = -1
-8x + 3 = -1
-8x = -4
x = 1/2

Plug x = 1/2 and y = 1 into first equation to check your answer:

88(1/2) - 5(1) = 39
44 - 5 = 39
39 = 39

Answer 3

Ok -so I assume you want to solve this as a system of linear equations. 2 equations - 2 unknows:

Solve
88x - 5y =39
-8x + 3y = -1; OK - lets multiply the bottom equation by 11

88x -5y =39
-88x + 33y = -11 ; now lets add the equations

28y = 28
y =1.

OK lets substitute the value of y into the first equation
88x - 5(1) = 39
88x -5 = 39
88x = 44
x = 1/2

So the answer is x = 1/2, y = 1.

Check in second equation

-8(1/2) + 3(1) = -1 ??
-4 + 3 = -1 ??
-1 = -1 YES!!

Hope this helps!

Answer 4

multiply the second equation by 11 then add the two equations:

11(-8x +3y) = 11(-1)
-88x + 33y = -11
+ 88x - 5y = 39

28y = 28
y = 1

88x - 5 = 39
88x = 44
x = 1/2

Answer 5

88x - 5y =39
-8x + 3y = -1 ---times by 11 ---- -88x+33y=-11
now add the second equation to the first

(88x-88x) + (-5y+33y) = (39-11)

28y=28
y=1

sub this back in to get x

-8x + 3(1) = -1
-8x= -1 -3
x= -4/-8
x= 1/2

Answer 6

88x - 5y = 39
-88x + 33y = - 11-----ADD
28y = 28
y = 1

88x - 5 = 39
88x = 44
x = 1/2

x = 1/2 , y = 1

Answer 7

88x - 5y = 39 and -8x + 3y = -1
88x - 8x - 5y + 3y = 39 - 1
80x - 2y = 38
therefore x = 1/2 and y = 1

Answer 8

So you have a couple of equations. What is your question?