Hi everyone, I'm sorry to ask the community for help but Algebra is killing me and if someone could give me a hand with this one I would greatly appreciate it.
Also, I'm practicing and going to start doing tutoring because I really want to learn how to do this one my one. But need some help on the fly if someone would be so kind.
Factor completely. 2b^2 + 7ab + 3a^2
2007-10-14 16:47:15 · 5 answers · asked by Jane S 1 in Science & Mathematics ➔ Mathematics
2b^2 + 7ab + 3a^2
Here, find two numbers such that their sum is 7 (coefficient of ab) and product is 6 (product of coefficients of b^2 and a^2).
Such numbers are 6 and 1. Now breakup the middle term 7ab as 6ab + ab and proceed as under.
2b^2 + 7ab + 3a^2
= 2b^2 + 6ab + ab + 3a^2
= 2b(b + 3a) + a(b + 3a)
= (b + 3a)(2b + a)
2007-10-14 16:54:52 · answer #1 · answered by Madhukar 7 · 0⤊ 1⤋
Factors are:-
( 2 b + a ) ( b + 3 a )
2007-10-14 23:53:56 · answer #2 · answered by Como 7 · 1⤊ 0⤋
2b^2 + 7ab + 3a^2
=(2b+a)(b+3a)
2007-10-14 16:50:59 · answer #3 · answered by tootoot 3 · 0⤊ 1⤋
(2b+a)(b+3a)
2007-10-14 16:51:51 · answer #4 · answered by ωĨŞΣ Ĝųγ 4 · 0⤊ 1⤋
Nevermind, they're right.
2007-10-14 16:55:07 · answer #5 · answered by Anonymous · 0⤊ 1⤋