2007-10-14 16:42:11 · 6 answers · asked by Nap 1 in Science & Mathematics ➔ Mathematics
12x*2.5/ sqrt x
2007-10-14 16:46:01 · answer #1 · answered by Erica 2 · 0⤊ 0⤋
f ( x ) = 6 x ² - 5 x^(1/2)
f `(x) = 12 x - (5 / 2) x^(-1/2)
f `(x) = 12 x - 5 / (2âx)
2007-10-15 07:07:52 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Multiply the exponent times the coefficient of each term and reduce the exponent by 1.
6x^2 --> 12x^1
5x^(1/2) --> 2.5x^(-1/2)
2007-10-14 23:46:57 · answer #3 · answered by Tom K 2 · 0⤊ 0⤋
I assume your problem is with the second term. Write it as 5x^1/2 before you begin. Then the derivative of that term becomes 2.5x^(-1/2).
2007-10-14 23:52:45 · answer #4 · answered by historian 4 · 0⤊ 0⤋
if you mean fifth root of x the answer is 12x - 1/5 times x to the negative four fifths. If you mean 5 times the square root of x the answer is 12x - five halves times (x to the negative onehalf). Or 12x - 5/(2times the square root of x)
2007-10-14 23:50:08 · answer #5 · answered by cris 2 · 0⤊ 0⤋
f(x)=6x^(2)-5sqrt(x)
f'(x)=12x-(5/2)(x^-1/)2
2007-10-14 23:45:49 · answer #6 · answered by ptolemy862000 4 · 0⤊ 0⤋