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the directions say simplify each expression, how would i simplify
x^2-16x+63
------------------
8x-56

2007-10-14 16:21:39 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

x^2 - 16x + 63 = (x-7)(x-9)



8x - 56 = 8(x-7)

ok thanks

2007-10-14 17:32:55 · answer #1 · answered by sanjeewa 4 · 0 0

The factored form of an expression is considered more simplified than the expanded form. Eliminating any factors that appear in both the numerator and the denominator also "simplify" an expression.

For x^2-16x+63, this would be (x-7)(x-9)

and for 8x-56, this would be 8(x-7).

Dividing the two, you cancel out the (x-7)'s to get (x-9)/8

2007-10-14 23:26:39 · answer #2 · answered by jruzzy 2 · 0 0

the easiest was is to just use the quadratic formula for the first one

if your equation is in the form ax^2+bx+c

then you use the formula

(-b+/- sqrt(b^2 - 4ac)) / 2a

otherwise a quicker way to factorise it is to ask what are the factors of 63 that add up to give -16

factors of 63 are ---- 63 and 1 , 21 and 3 , 9 and 7

now 9 and 7 multiplyed together equals 63 and added together gives 16

-9 and -7 multiplied together gives 63 and added gives 16 so these are your factors

put them in brackets with x

(x-7)(x-9)




for the second one it is plain to see that 56 is a factor of 8 so all you need to do is take 8 out of the equation
8x-56 = 8(x-7)

2007-10-14 23:51:43 · answer #3 · answered by Anonymous · 0 0

try completing the square..so the first one would be (x-7)(x-9) and the second one could possibly be 8(x-7)

the first one is cuz when you multiply -7 and -9, you get 63, and when you add -7 and -9, you get 16 ...when you multiply it out...you get x^2-16x+63

and the second one, you take out the 8 from the x...and the 8 from the 56, so you divide 8 from 56

hope it helped :)

2007-10-14 23:27:59 · answer #4 · answered by luvwithurheart 3 · 0 0

x^2 - 16x + 63 = (x-7)(x-9)
8x - 56 = 8(x-7)

(x^2-16x_63)/(8x-56) = (x-9)/8

2007-10-14 23:25:56 · answer #5 · answered by norman 7 · 0 0

complete the square of nominator:
(x^2-16x+64)-64+63 => (x-8)^2-1
8x-56 => factor out 8: 8(x-7)
you are left with:
(x-8)^2-1
--------------
8(x-7)
simplified!

2007-10-14 23:30:02 · answer #6 · answered by Hassoun 2 · 0 0

Factor denominator and numerator as far as you can

(x - 9) (x - 7)/ 8(x -7)

Then cancel out (x - 7) from numerator and denominator
(x - 9) / 8

2007-10-14 23:28:35 · answer #7 · answered by G.V. 6 · 0 0

x^2 - 16x + 63
_______________
8x - 56

= (x - 9) (x - 7)
______________
8 (x - 7)

= (x - 9)/8

2007-10-14 23:31:03 · answer #8 · answered by rooster1981 4 · 0 0

(x - 9)(x - 7)
---------------
8(x - 7)

(x - 9)
-------
8

2007-10-16 04:07:52 · answer #9 · answered by Como 7 · 0 0

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