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ahhh please help!!!
pre cal prob!

2007-10-14 16:05:05 · 5 answers · asked by icygurl555 1 in Science & Mathematics Mathematics

5 answers

pretty simple.. juz use -2 in place of x.

f(-2) = -(-2)^2 - (-2) -8
= -(4) + 2 - 8
= 10

2007-10-14 16:13:23 · answer #1 · answered by ginchan 3 · 0 1

Substitute -2 for X in the given equation.
You should come up with
-4+2-8=-10

2007-10-14 23:10:59 · answer #2 · answered by vcs7578 5 · 1 0

f(x)=-x^2-x-8

first of allll
f(x) = y
ok so then.....
replace the x values with -2

f(x)=-x^2-x-8
f(-2) = -(-2)^2 - (-2) - 8
f(-2) = -(4) + 2 - 8
f(-2) = -2 - 8
f(-2) = -10


beleive this should be right
i learned this a few weeks ago max, so i should know it,. i hope, lol :P

hope this helped

2007-10-14 23:10:36 · answer #3 · answered by Nick723 3 · 2 0

f ( - 2 ) = - ( - 2 ) ² + 2 - 8
f ( - 2 ) = - 4 - 6
f ( - 2 ) = - 10

2007-10-15 10:06:58 · answer #4 · answered by Como 7 · 1 0

f(x)=-x^2-x-8
x=-2
f(-2) = -(-2)^2 - (-2) - 8
f(-2) = -(4) + 2 - 8
f(-2) = -2 - 8
f(-2) = -10

2007-10-15 00:54:08 · answer #5 · answered by sanjeewa 4 · 1 0

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