2007-10-14 14:55:15 · 8 answers · asked by dr.whooo 2 in Science & Mathematics ➔ Mathematics
x^2 - 13 = 3^5 = 243
x^2 - 13 = 243
x^2 = 256
x = +/-16
2007-10-14 14:58:14 · answer #1 · answered by UnknownD 6 · 0⤊ 0⤋
First raise both sides to the power of 5, it'll cancel out the 1/5 power.
So, x^2-13=3^5
x^2-13=243
Then you add 13 to both sides
x^2=256
Then you take the square root of both sides
x= rt256
So, x=16
2007-10-14 22:01:49 · answer #2 · answered by penny 3 · 0⤊ 0⤋
x ² - 13 = 3^5
x ² - 13 = 243
x ² = 256
x = ± 16
2007-10-16 06:14:43 · answer #3 · answered by Como 7 · 0⤊ 0⤋
1) Divide both sides of the equation by (1/5)
2) Add 13 to both sides of the equation
3) Take the square root of both sides of the equation
You'll be left with X = ??
2007-10-14 21:58:22 · answer #4 · answered by arkleseizure 3 · 0⤊ 1⤋
(3^5)^(1/11)=.606913365 or 3^(-5/11) or the -11th root of 3 to the 5th power
Just work backwards throught the order of opperations
2007-10-14 22:03:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x^2-13)^(1/5)=3
x*2^1/5 -2.6=3
+2.6 +2.6
x*2^1/5 = 5.6
.4x=5.6
/.4 /.4
X=16
Check: (16^2-13)^(1/5)=3
(256-13)^(1/5)=3
256^(1/5)= 3.03
2007-10-14 22:03:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋
x=+/-16
2007-10-14 22:42:15 · answer #7 · answered by rfiskt 2 · 0⤊ 0⤋
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2007-10-14 22:00:26 · answer #8 · answered by Anonymous · 0⤊ 0⤋