How do you solve this guys and girls help me.
Radical 98x^3 / rad 2x
If anyone can help me with this problem i will appreciated ♥
2007-10-14 14:30:09 · 4 answers · asked by HEy 3 in Science & Mathematics ➔ Mathematics
√(98x3) = 7x√(2x)
so the √(2x) in the denominator will just cancel together with the one in the numerator
so the answer will just be 7x
hope this helps...
2007-10-14 14:39:18 · answer #1 · answered by forgetfulpcspice 3 · 0⤊ 0⤋
98x^3/[2x]^.5 The square root of a number x is the number x to the one half power. Using the laws of exponents, you subtract the exponent in the denominator from the exponent in the numerator since they have the same base: x This gives: [98/sqrt2][x^2.5]=sqrt2*49*x^2.5 Notice that x^2.5 is x^[5/2]=sqrt[x^5]
2007-10-14 14:43:19 · answer #2 · answered by oldschool 7 · 0⤊ 0⤋
I assume by "solve" that you mean "simplify".
â(98x³) / â(2x) = â[(98x³)/(2x)] = â(49x²) = â(7²x²) = 7x
2007-10-14 14:42:42 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋
sqrt(98x^3)/sqrt(2x)
= sqrt(98x^3/2x)
= sqrt(49x^2)
= +/- 7x
2007-10-14 14:43:39 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋