A spring with spring constant k = 60 N/m and unstretched length of L0 is attached to the ceiling. A block of mass m = 1 kg is now hung on the end of the spring and is gently lowered.
a) How far does the spring stretch?
A chemistry student now pulls the block down until the total amount the spring is stretched is twice the amount found in part (a).
b) Assuming the mechanical energy of the block to be zero when the spring is in its unstretched position, what is the potential energy of the block when it is held in this new position?
c) What is the total mechanical energy of the block when it is this new position?
The block is now released and pushed upward with an initial speed vi = 2 m/s. d) What is the maximum speed of the block?
pic: https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/Phys1201/fall/homework/Ch-08-Energy-Conservation/mass_vertical_spring/vertical-spring.jpg
2007-10-14 14:00:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
F=-kx
F=mg
x= -mg/k=1 x 9.81/60=.164m= 16.4m
2007-10-16 10:36:41 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
Use the formula of skill skill saved contained in the spring = kinetic skill of the ball a million/2 ok x^2 = a million/2 m v^2 ok x^2 = m v^2 v =x* sqrt(ok/m) = 0.one hundred ten * sqrt (820/0.500) = 4.455 m/s
2016-10-21 04:22:07 · answer #2 · answered by ? 4 · 0⤊ 0⤋