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A system contracts from an initial volume of 15.0 L to a final volume of 10.0 L under a constant external pressure of 0.800 atm. The value of w, in J, is

2007-10-14 13:52:44 · 1 answers · asked by cpistone7 2 in Science & Mathematics Chemistry

1 answers

1 atm can also be stated as:
1atm
≡1.013 25 bar
≡101.325 kPa
≡760 torr [B]
≈760.001 mm-Hg
≈1.033 227 452 799 886 kgf/cm²
Hence w = P(V2-v1) = 0.800atm*5.0L
= (0.800atm)*(1.033*9.80N/cm²atm)*(50m*cm^2)
= 0.405 kJ

2007-10-17 13:57:29 · answer #1 · answered by Hahaha 7 · 0 1

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