physics kinematics in two dimensions?

Question

An airplain is flying at 240m/s at an angle of 30 degrees with the horizontal. when the altitude of the plane is 2.4km, a flare is realiease. the flare hits the target on the ground, wat is the angle?

How do i even approach this i feel as if there isn't enough info

From a 60m cliff a rocket is launched upwards with Vo = 23 m/s at an angle of 50 degrees with respect to the horizontal. At what point above the ground does the rocket strike the wall of a vertical cliff located 20m away?

Answer 1

The only thing I see missing is whether the 30 degrees above the horizontal or below. Is the plane diving or climbing? Assuming you know, I can help with the rest.

Break the flare's original velocity into vertical and horizontal components. The horizontal veocity will remain constant (we have to assume no air resistance since it's not mentioned). The flare will be in free fall so that the vertical component of its velocity increases due to gravity. Use
Vf^2 = Vo^2 + 2*g*h

Then combine the horizontal velocity with the new vertical into a final resultant velocity.

***

We have to assume the rocket is not powered since no info is given about thrust. I guess it's like it was shot out of a gun. Again, break Vo into horizontal, Vox, and vertical, Voy.

You can get the time of flight from Vox and the distance to the other cliff. Then in that amount of time, where is it vertically?
y = Voy*t + (1/2)*(-g)*t^2

I said (-g) because I defined in my head that up is the positive direction and g operates in the negative direction. Note, y will be with respect to the launch elevation.