An ideal gas is confined in a cylinder at 20 C and a pressure of 4 atm.
1. If the cylinder is surrounded by boiling water and allowed to come to equilibrium, what will the pressure of the gas be?
2. If the gas is allowed to escape until the pressure again reaches 4.0 atm, what fraction of the original gas, by weight, will escape?
3. If the temperature of the remaining gas now returns to 20 C, what is its pressure?
I'm so lost, please explain and show your work so that I may follow.
2007-10-14 13:48:22 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
1. The value of p*V/T before will be the same as after where p is pressure, V is volume, and T is temperature in degrees Kelvin. So
p1*V1/T1 = p2*V2/T2
The volume stays constant so it cancels out and T2 will increase from 20 to 100 degrees. Plug the 2 temps in and the original pressure, solve for p2.
2. You found the pressure in #1. Whatever that ratio to 4 atm is, that's the factor of the quantity of gas allowed to escape.
3. Go back to the procedure of #1.
2007-10-14 15:22:54 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋