hey pls help me with thathow can we multiply (6+x)*(38+x)?

Answer 1

FOIL

first 6*38 = 228
out = 6*x = 6x
in = 38*x = 38x
last = x*x = x^2

(6+x)(38+x) = 228 + 44x + x^2

Answer 2

If you had x(38+x) what would the result be?

x*38 + x*x

Now, you can solve the problem with FOIL, but if this helps you you could do this:
(6+x)*(38+x) = 6*(38+x) + x*(38+x)
= 6*38 + 6*x + x*38 + x^2
= 228 + 44*x + x^2

Answer 3

(6 + x) (38 + x)
228 + 6x + 38x + x ²
228 + 44 x + x ²

Answer 4

(6+x)(38+x)
=228 + 44x + x^2
= x^2 + 44x + 228

Answer 5

Use FOIL. multiply the First numbers of both quantities. then the outside numbers. then the inside numbers. then the last numbers.

(x*x)+44x+248=0

Use quadriatic formula

-44+or- the square root of 44 squared-4*248. then divide the whole thing by 2

Answer 6

distribute ...
(6 + x)(38 + x)
= 228 + 6x + 38x + x^2
(collect like terms)
= 228 + 42x + x^2

Answer 7

hold on

You multiply by using FOIL

(6+x)(38+x)

38*6+6x+38x+x^2
228+44x+x^2

So you end up with xsquared plus 44x plus 228

x^2 + 44x + 228

Hope this helps

Answer 8

FOIL:

multiply the First terms
multiply the Outside terms
multiply the Inside terms
multiply the Last terms

combine like terms (in this case, you'll have one constant, two terms with x, and one term with x^2) and there you go.