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a grocer displayed 66 cans of corn in the form of a pyramid which had one can on top, 2 cans below it, 3 cans below that, and so on. how many cans were there in the lowers layer?

I HAVE TO USE THE ARITHMETIC SEQUENCE EQUATIONS!!!

2007-10-14 11:06:02 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

n1 = 1 and d = 1 n(t) = 1 + (t-1)

s(t) = (1+ 1+(t-1)) t/2 = 66
t^2 + t = 132
t^2 + t -132 = 0
(t-11)(t+12)=0
t = 11
so the lower layer = 1 + (11-1) = 11

2007-10-14 11:19:33 · answer #1 · answered by norman 7 · 0 0

1 + 2 + 3 + ... + n = 66
n(n+1)/2 = 66
n(n+1) = 132
11(12) = 132
n = 11 layers.
Now, your question, "how many cans were there in the lowers layer," doesn't make a lot of sense.
Lower than what? Lower than the 3 you mentioned? Six cans in the top 3 layers, obviously 60 cans in the lower 8 layers.

2007-10-14 18:25:05 · answer #2 · answered by Philo 7 · 0 0

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