help me in solving this equation?

0 ⤊

3(y-1) / (5) + 4 = y???

2007-10-14 10:58:09 · 3 answers · asked by luishernandez66 1 in Science & Mathematics ➔ Mathematics

3y - 3 + 20 = 5y
2y = 17
y = 17/2 = 8 1/2

2007-10-14 11:03:06 · answer #1 · answered by norman 7 · 0⤊ 0⤋

3y -3 + 20 = 5 y
2y =17
y = 17 / 2

2007-10-14 11:01:24 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋

3(y-1) / (5) + 4 = y
5[3(y-1) / (5) + 4 = y]
(y-1) + 20 = 5y
y-1+20=5y
y+19=5y
y-5y=-19
-4y=-19
y=19/4

2007-10-14 11:04:30 · answer #3 · answered by noah_greifer 2 · 0⤊ 0⤋