(-4*a)/(y) + (2*a) / (4*a) + (4*a)/(y)? Need help....
2007-10-14 10:40:32 · 4 answers · asked by luishernandez66 1 in Science & Mathematics ➔ Mathematics
If I read this correctly you have three fractions. The first and the third are algebraically the same except that one is negative and the other is positive. So they cancel each other out and you're left with the one in the middle. This simplifies to 1/2 or one half.
(-4*a)/(y) + (2*a) / (4*a) + (4*a)/(y)
= (2*a) / (4*a) = 2/4 =1/2
2007-10-14 10:47:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
-4a/y + 2a/4a + 4a/y
The first and last fractions are opposites of each other, so when you add them together you get 0:
(-4a+4a)/y = 0/y = 0
So you are just left with he middle fraction, 2a/4a.
When you divide 2 by 4, you get 1/2 and when you divide a by a you ge 1. So the answer is just 1/2.
1/2
Good luck!
2007-10-14 17:45:04 · answer #2 · answered by tsully87 3 · 1⤊ 0⤋
You're joking, right?
The first and the third terms cancel each other leaving 2a/4a= 1/2
2007-10-14 17:46:08 · answer #3 · answered by LucaPacioli1492 7 · 0⤊ 0⤋
(-4*a)/(y) + (2*a) / (4*a) + (4*a)/(y)
=-4a/y+1/2+4a/y=1/2
2007-10-14 17:44:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋