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For any integer k>1, k! is the product of every integer from 1 to k. Thus, 3! = 1x2x3. Write the only integer n>32 that satisfies:
(n-23)!(23)! = (n-32)!(32)!

2007-10-14 09:42:41 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

(n-23)! / (n-32)! = 32!/23!

so n - 23 = 32
and n - 32 = 23

n = 55

2007-10-14 10:08:38 · answer #1 · answered by J D 5 · 0 0

55

2007-10-14 17:50:41 · answer #2 · answered by ironduke8159 7 · 0 0

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