How do you differentiate a(s)=-((12)/(s^5))?

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thanks for any help you can provide!

2007-10-14 09:08:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1/s^5 = s^(-5)

a(s) = -12(s^(-5))

=(-12)(-5)s^(-4)
=60s^(-4)
or 60/(s^(-4))

2007-10-14 09:19:14 · answer #1 · answered by sweetchik5188 2 · 0⤊ 0⤋

= -12*s^-5
= -12 (-5) s^-6
= 60 / s^6

2007-10-14 09:20:22 · answer #2 · answered by J D 5 · 0⤊ 1⤋

Uuse quotient rule:
a(s) = -12/s^5
a'(s) =- (-12*5s^4/s^10
a'(s) = 60/s^6

2007-10-14 09:19:50 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋

This puzzles me too

2016-07-30 05:19:16 · answer #4 · answered by ? 3 · 0⤊ 0⤋

thanks to each and everyone of you guys for the replies!

2016-08-26 02:55:05 · answer #5 · answered by Anonymous · 0⤊ 0⤋