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A diver running 1.6 m/s dives out horizontally from the edge of a vertical cliff and 2.9 s later reaches the water below.
How high was the cliff?
m
How far from its base did the diver hit the water?
m

2007-10-14 09:06:28 · 1 answers · asked by kdcheerldr 1 in Science & Mathematics Physics

1 answers

The height of the cliff is found by using y = 0.5*gt^2, where g is the acceleration due to gravity (g = 9.8 m/s^2) and t is the elapsed time, which you were given.

The horizontal distance traveled is found by simply taking (v_x)t, where v_x is the horizontal velocity at the point of departure (the top of the cliff) and t is the elapsed time, both of which you were given.

2007-10-17 08:59:39 · answer #1 · answered by DavidK93 7 · 0 0

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