The line connecting the midpoints of two sides of a triangle is || to the 3rd side and = to 1/2 its length.
Therfore the triangle formed by connecting all three midpoints is similar to the original triangle and has each of its sides equal to 1/2 of the corresponding sides of the original triangle.
hence its area is 1/4 that of the original triangle
2007-10-14 07:26:39
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answer #1
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answered by ironduke8159 7
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Yes, it is 1/4 the original area, because it will separate the Big triangle into 4 small ones, each with 1/4 the total area.
Props to mikagami715 for getting it right first.
2007-10-14 07:15:46
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answer #2
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answered by Jeffrey C 1
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E is the midpoint of BC and CE = 7, so BE = 7 F is the midpoint of CA and AF = 6, so CF = 6 the fringe, he distance around the fringe of the triangle is 36, so AB + BC + CA = 36 BE = 7 and EC = 7, so BC = 14 CF= 6 and FA = 6, so CA = 12 So then we plug this into the fringe formula: AB + BC + CA = 36 AB + 14 + 12 = 36 AB = 10 Now all individuals understand D is the midpoint of AB and AB = 10, so ad would properly be 5.
2016-10-21 03:49:45
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answer #3
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answered by Anonymous
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You get 4 congruent triangles when this happens so the new triangle is 1/4 of the original.
2007-10-14 07:14:31
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answer #4
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answered by hayharbr 7
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its always 1/4 of the area of the original triangle..
2007-10-14 07:13:34
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answer #5
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answered by mikagami715 1
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half the area of the original triangle
2007-10-14 07:13:31
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answer #6
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answered by ib 4
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Use a coordinate plane (graph paper).
A(0,0) and B(b,0) and C(0,c)
with midpoints
D(b/2,c/2) and E(b/2,0) and F(0,c/2)
After connecting the points, you get two right traingles with areas: bc/2 and bc/8
[ bc/8 ] / [ bc/2 ]
[ bc/8 ][ 2/bc ]
[ 1/4 ]
2007-10-14 07:22:09
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answer #7
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answered by Anonymous
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I'm no mathemetician, but it seems to me the three lines would intersect...the area they comprise would be zero.
2007-10-14 07:14:06
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answer #8
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answered by Perky_gurl 4
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the hypotnuse??
2007-10-14 07:20:15
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answer #9
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answered by Anonymous
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