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the legths of 2 sides of a triangle are 12 and 2 , respectivly, what is one posible legth of the 3rd side??

2007-10-14 06:43:15 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

does it not matter what type of triangle it is?

2007-10-14 06:45:35 · answer #1 · answered by Beckahxo 2 · 0 2

the legths of 2 sides of a triangle are 12 and 2 , respectivly, what is one posible legth of the 3rd side??

let's assume we have a right triangle with sides 2 and 12
the 3rd side is just
sqrt(2^2+12^2) = sqrt (148)
approximately = 12.165 units.

2007-10-14 06:53:38 · answer #2 · answered by Any day 6 · 0 0

( 3, 4, 5) ( 5, 12, 13) ( 7, 24, 25) ( 8, 15, 17)
( 9, 40, 41) (11, 60, 61) (12, 35, 37) (13, 84, 85)
(16, 63, 65) (20, 21, 29) (28, 45, 53) (33, 56, 65)
(36, 77, 85) (39, 80, 89) (48, 55, 73) (65, 72, 97)

If it is a multiple of any of these Pythagorean triples then that would be the answer.

2007-10-14 06:48:32 · answer #3 · answered by noneofyourbusiness1300 2 · 0 1

Let x = length of third side
Then 12+2 >x
14 > x
The sum of two sides of a triangle must be greater than the 3rd side.
x+2> 12
x>10
So 10

2007-10-14 06:51:28 · answer #4 · answered by ironduke8159 7 · 0 0

10.1
all the lengths from 10.00001 to 13.9999 are possible.
if a right triangle with these two as the outside 12.1665 is hypotenuse. sqrt(2^2 + 12^2)
if 12 is hypotenuse then sqrt (12^2 - 2^2) = 11.832

2007-10-14 06:49:59 · answer #5 · answered by Mike1942f 7 · 0 0

Since the sum of any 2 sides of a triangle have to be bigger then the third side the only answers can be inbetween 10.1 and 13.9

2007-10-14 06:50:04 · answer #6 · answered by Rutgers101 2 · 0 0

Any number between 10 and 14, but not 10 or 14

You get this by:
12-2=10
12+2=14

So your equasion could be 10
your number could be...lets say...11

EDIT: ^^ he beat me to it =( ^^

2007-10-14 06:52:57 · answer #7 · answered by da pie 3 · 0 0

not enough information to solve this one

2007-10-14 06:46:32 · answer #8 · answered by Mike G 4 · 0 1

12.16553

2007-10-14 06:45:49 · answer #9 · answered by tony g 2 · 0 1

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