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4 answers

you cant graph this because the first one is not linear!!!

2007-10-14 05:55:07 · answer #1 · answered by 777 6 · 0 1

Set the two lines equal to each other

x^3+2x-1=2x+15

Isolate x

x^3=16

x=(16)^1/3 or x=5.33

2007-10-14 05:56:05 · answer #2 · answered by rfiskt 2 · 0 1

nicely in case you have a 'Texas device TI-80 4' calculator then you certainly could in simple terms placed it interior the y= button then click graph.....or the slope often is the -2 and the y intercept +a million so get on the a million and flow down 2 suited a million=)

2016-10-22 09:22:06 · answer #3 · answered by ? 4 · 0 0

y=x^3+2x-1 and y=2x+15
x^3+2x-1=2x+15
x^3 = 16
x = 2*2^(1/3)
x = approximately 2.5198421

2007-10-14 06:00:52 · answer #4 · answered by ironduke8159 7 · 1 0

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