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A harmonic wave, has a wavelength λ, a period Τ and an amplitude Α.Find the distance y from the equillibrium , the moment t=Τ/4 and when x=λ/6.

the equation of the y is : y=A*sin[2π(t/T - x/λ)]

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2007-10-14 05:08:22 · 1 answers · asked by Joey 1 in Science & Mathematics Physics

1 answers

I hope I'm in time to save you

Since : y=Asin[2π(t/T - x/λ)]
y(T/4)=Asin[(2π(T/4)/T - (λ/6)/λ)]

y(T/4)=Asin[2π( (1/4) - (1/6) ) ]

y(T/4)=Asin[π/6 ] = (1/2)A

Well was I?

2007-10-17 07:35:42 · answer #1 · answered by Edward 7 · 0 0

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