2x^2 - x - 3 = 0
2007-10-14 04:58:33 · 11 answers · asked by Horsecraz4eva 2 in Science & Mathematics ➔ Mathematics
2x^2 - x - 3
NB You need to find two number which when multiplied give '3' : 3 x 1 = 3
& two more numbers which when multiplied give '2' : 2 x1 =2
By cross multiplying these numbers and adding to reach 'minus 1'
( 2x - 3)(x + 1) = 0 the ANSWER.
As a verification use FOIL and see if it results in the original statement.
(2x - 3)(x + 1)
2x^2 + 2x - 3x -3 collect like terms.
2x^2 - x - 3
2007-10-14 05:09:26 · answer #1 · answered by lenpol7 7 · 0⤊ 0⤋
2x^2 - x - 3 = 0
(2x + 2)(x - 1) = 0
2007-10-14 12:12:12 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
2x^2- x- 3= 0
(2x - 3) (x + 1)
2007-10-14 12:07:37 · answer #3 · answered by dzuy n 1 · 0⤊ 0⤋
2x^2+3
2007-10-14 12:06:40 · answer #4 · answered by Beep B 5 · 0⤊ 1⤋
(2x-3) (x+1)=0
2007-10-14 12:01:43 · answer #5 · answered by Ehrykkh 3 · 1⤊ 0⤋
(x+1)(2x-3)
x= -1 x=3/2
2007-10-14 12:01:35 · answer #6 · answered by Anonymous · 1⤊ 1⤋
2x^2 - x - 3 = 0
let's find the roots of this equation
x' = [ +1 + sqrt.(1 -4(-3*2))/4
x' = [+1 + sqrt.(25)]/4
x' = [6]/4
x' = 3/2
x'' = [+1 - sqrt.(25)]/4
x'' = [-4]/4
x'' = -1
(x - 3/2)(x + 1) = 0
2x^2 - x - 3 = 0 <==> (2x - 3)(x + 1) = 0
2007-10-14 12:11:15 · answer #7 · answered by Christine P 5 · 0⤊ 0⤋
(2x - 3)(x+1)
2007-10-14 12:02:42 · answer #8 · answered by Cricket R 2 · 1⤊ 0⤋
(x+1) (2x-3)
2007-10-14 12:01:51 · answer #9 · answered by Anonymous · 1⤊ 0⤋
( 2 x - 3 ) ( x + 1 ) = 0
x = 3 / 2 , x = - 1
2007-10-14 14:43:27 · answer #10 · answered by Como 7 · 0⤊ 0⤋