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A harmonic wave, has a wavelength λ, a period Τ and an amplitude Α.Find the distance y from the equillibrium , the moment t=Τ/4 and when x=λ/6.

the equation of the y is : y=A*sin[2π(t/T - x/λ)]

heeeelp plz!!!!!!!!!!!!!

2007-10-14 04:37:40 · 1 answers · asked by Joey 1 in Science & Mathematics Physics

1 answers

Um, instead of writing this question just write in the values for t and λ, namely

y = Asin(2π(1/4 - 1/6)) = Asin(π/6)

2007-10-14 04:45:04 · answer #1 · answered by supastremph 6 · 0 0

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