how do i simplify
√6/√7 x √14/√3
2007-10-14 04:14:14 · 4 answers · asked by sumguy 1 in Science & Mathematics ➔ Mathematics
It actually works just like 6/7 x 14/3...
√14 = √7√2, so
√6/√7 x √14/√3 =
√6/√7 x √2√7/√3
√7s cancel, so you have
√6 x √2/√3
then √6 = √2√3, so, substituting:
√2√3 x √2/√3
√3 cancels in numerator and denominator, leaving:
√2 x √2 = 2
2007-10-14 04:24:28 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
â6/â7 x â14/â3= â84/â21 =â4 = 2
2007-10-14 11:36:06 · answer #2 · answered by jen ol 3 · 0⤊ 0⤋
â6 / â7 x â14 / 3 =
â84 / â21 =
Rationalizing the denominator
â84 â21 / â21 / 21 =
â1764 / â441
Square root the numerator and denominator
42 / 21 =
2
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2007-10-14 12:15:06 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
sqrt(6)sqrt(7)=sqrt(42)
sqrt(14)sqrt(3)=sqrt(42)
sqrt(42)sqrt(42)=42
2007-10-14 11:37:16 · answer #4 · answered by cidyah 7 · 0⤊ 0⤋