2007-10-14 02:40:37 · 8 answers · asked by Dylan Rose 1 in Science & Mathematics ➔ Mathematics
Do your own homework ya oik.
2007-10-14 02:42:59 · answer #1 · answered by Blokheed 5 · 2⤊ 0⤋
logx (base 5) + 4log2 (base 5) = 2log8 (base 5)
logx (base 5) + log2^4 (base 5) = log8^2 (base 5)
logx (base 5) = log8^2 (base 5)- log2^4 (base 5)
logx (base 5) = log(8^2/2^4) (base 5)
logx (base 5) = log(64/16) (base 5)
logx (base 5) = log(4) (base 5)
5^x=5^4
x=4
2007-10-14 02:57:33 · answer #2 · answered by Anonymous · 0⤊ 1⤋
You should know this rule that applies, provided the logs are the same base.
loga + logb = logab
Also log a^n = n log a
simplifing using the above rules. (I will not bother writing base 5)
logx +log2^4 = log8^2
log16x = log 64
16x = 64
x=4
2007-10-14 02:50:32 · answer #3 · answered by Peter m 5 · 0⤊ 1⤋
Assume log is log to base 5 in the following:-
log x + 4 log 2 = 2 log 8
log x + log 2^4 = log 8²
log x + log 16 = log 64
log x = log 64 - log 16
log x = log ( 64 / 16 )
log x = log 4
x = 4
2007-10-14 03:03:35 · answer #4 · answered by Como 7 · 0⤊ 1⤋
2^4 x = 8^2
16x = 64
x = 4 ( base 5)
2007-10-14 02:45:56 · answer #5 · answered by jen ol 3 · 0⤊ 1⤋
log x + 4 log2 = 2log 8
log 16x =log 64
16 x =64
x = 4
all logarithms are in base 5
2007-10-14 02:43:30 · answer #6 · answered by Ivan D 5 · 0⤊ 1⤋
You got a calculator? I've run out of toes!
Shi*e I've forgot, I've not got any.
Waaaaaaaaaaaaaaaaaaa!
Nessie.
Ps Ivan is a smart a*se. (see above)
2007-10-14 02:44:36 · answer #7 · answered by Nessie from Loch Ness 6 · 1⤊ 1⤋
Are you too lazy to do your own homework?
Or are you too stupid to do your own homework?
It has to be one or the other.
2007-10-14 02:51:18 · answer #8 · answered by Swampy_Bogtrotter 4 · 0⤊ 0⤋