Find the altitude (or height) of the triangle sides are 13 base is 10?

Answer 1

Assuming it's an isosceles triangle, with each of the other two sides being 13 and the base being 10, the height will bisect the 10 side, creating two right triangles with one side being 5 and the hypoteneuse being 13. Using the Pythagorean theorem, the height is then sqrt (13^2 - 5 ^2) = 12.

Answer 2

It is an isosceles triangle with length of equal sides = 13.
Let h = length of altitude on base of length 10.
Then this altitude bisects the base perpendicularly.

By Pythagoras theorem,
h^2 = 13^2 - 5^2 = 12^2
=> h = 12.

Answer 3

12. If both aspect are 13 and the bottom is 10, then in case you draw a line immediately down the middle from the right, it's going to make a perpendicular bisector with the bottom which will divide the given triangle into 2 top triangles. those top triangles may have one aspect it really is 5, and the hypotenuse will be 13. So, we will use the Pythagorean Theorem: a^2 + b^2 = c^2 ==> plug in aspect 'a' and hypotenuse 'c' 5^2 + b^2 = 13^2 ==> evaluate exponents 25 + b^2 = 169 ==> subtract 25 on both aspect b^2 = one hundred forty four ==> sq. root both aspect b = 12.

Answer 4

A right angle triangle can be made by half of this triangle. Where base=5, hypotenuse=13 and the height is what you are trying to find. You can then use Pythagoras' theorem
h^2=a^2+b^2
where h=hypotenuse, b= base and a=altitude.
then it is just a case of
a^2=h^2-b^2
a^2=(13^2)-(5^2)
a^2=169-25
a^2=144
a=sqrt(144)
a=12
Good luck! :)

Answer 5

Split the base in half this will give you a right triangle with a short leg of 5 and the hypotenuse of 13 ...use Pythagorean theorem to solve for long side(heigth)...here's the formula
hyp= square root of the sum of the other two sides squared
c=sqrt a^2+b^2
try this ...from the E...