The distance across a circular wheel, regardless of how many times it spins is its diameter (twice the radius)
If you mean what is the length marked out by the wheel rolling, that is 30 times the circumference (2 x pi x radius), for a total of 12pi.
2007-10-14 01:40:08
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answer #1
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answered by Tunips 4
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across the wheel is just 0.4
However if you are looking for the distance its moved you need to work out the circumferance:
C=2rpi
=2x.2.pi
=1.25664m
Then
C x no of revolutions
= C x 30
= 37.7
2007-10-14 01:38:25
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answer #2
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answered by Tom W 2
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For a lot of those questions, i discover it usefult to continuously record what i comprehend in the beginning ... r = 30 feet v = 3.5 rev/min The circumference of the wheel is .. C = 2*pi*r C = 2 * 3.14 * 30 feet C = 188.4 feet the great distance travelled in a million minute is d = C * v * t d = 188.4 * 3.5 * a million d = 659.4 feet as a result the linear speed of a seat on the ferris wheel is 659.4 feet/min.
2016-12-29 08:41:05
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answer #3
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answered by Anonymous
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Assuming that your question is to have the dist that travelled by the whell in 30 rev.
1 revolution = 3.1416*0.2*2 = 1.26 unit (coz no mentioned unit)
30 rev = 1.26 * 30 = 37.70 units
but if you mean that the dist across the wheel, equals 0.4 unit.
2007-10-14 01:46:40
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answer #4
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answered by Synchronizers 3
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It depends on the material of the wheel since after 30 revolutions it has the potential to have compressed/chiped away.
2007-10-14 01:49:06
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answer #5
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answered by drewder 2
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If you mean the distance it has travelled, the answer is 37.7
(0.2 x 2) x pi x 30 = 37.7
or
(radius x 2) x 3.1415927 x 30 =37.7
2007-10-14 01:40:43
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answer #6
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answered by Michael B 6
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r=0.2
The circumference c=2*pi *r
so 30 times the revolution will be 30 c =d
d= 30 *c = 30*2*pi *.2
d =37.699
2007-10-14 01:42:37
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answer #7
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answered by rsraszka 3
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