a^4 - 7a³b + a²b²
____2a³b - 14a²b² + 2ab³
________ - a²b² ___7ab³___- b^4
a^4 - 5a³b - 14a²b² + 9ab³ - b^4
2007-10-17 20:19:18
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answer #1
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answered by Como 7
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(a^2 + 2ab - b^2)(a^2 - 7ab + b^2)
so what you need to do is distribute each number in the right parenthesese with each number in the left.
a^4 - 7a^3b + a^2b^2 +2a^3b - 14a^2b^2 + 2ab^3 - b^2a^2 + 7ab^3 - b^4
Now you can simplify, first understand that a^2b^2 and -a^2b^2 cancel out because they are opposites (negative and positive)
a^4 - 5a^3b - 14a^2b^2 +9ab^3 - b^4
And this is the final answer
2007-10-14 08:47:47
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answer #2
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answered by Austin 2
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(a^2 + 2ab - b^2)(a^2 - 7ab + b^2)
=a^4 - 7a^3b + a^2b^2+2a^3b-14a^2b^2+2ab^3+a^2b^2-7ab^3+b^4
=a^4 - 5a^3b - 12a^2b^2 - 5ab^3 + b^4
2007-10-14 10:39:40
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answer #3
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answered by navya 1
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a^4 - 5a^3b - 14a^2b^2 + 9ab^3 - b^4
2007-10-14 08:36:32
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answer #4
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answered by kavitasingit 1
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Kudos to Butchy there. It's not that hard, just do a kind of Foil thing, it won't take long.
2007-10-14 08:29:30
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answer #5
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answered by Genie 2
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If I answer this, all you are learning is how to be a leech. Carry you own weight. Do it yourself. I'm sure your teacher provides time to answer questions. He/she is who you should be asking for help.
2007-10-14 08:34:08
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answer #6
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answered by Smoothie 5
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(a^4)-(5a^3)b-14(a^2)(b^2)+9(a^2)(b^3)-(b^4)
2007-10-14 08:33:32
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answer #7
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answered by ron b 1
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No, you should have been paying attention in class. 2 points please
2007-10-14 08:26:55
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answer #8
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answered by Butchy boy 2
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can be reduced to :
(2a+2b+6) (3a-7-b)
I think
SO it would be:
5a+3b+13=SOmething...................................
2007-10-14 08:28:36
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answer #9
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answered by Anonymous
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twenty eleven.
2007-10-14 08:26:41
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answer #10
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answered by Anonymous
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