Will someone plz help me on how to find out the electron configuration of an element?

Question

I need to learn how to figure out the electron configuration of an element by just looking at the periodic table, plz do help, and thanks!

Answer 1

First, you have the "main-line" groups, such as the IA, 2A, 3A, 4A, 5A, 6A, 7A, and 8A. With elements in these groups, the OUTER electron shells are filled in the order 1s, 2s, 2s1p, 2s2p...
2s6p.
The elements Lithium to Neon and
Sodium to Argon follow this.
In the next level(4), everything goes cool until you pass Sc. Then you run into the 10 3d- transition elements. Then the rest of the level reverts to the main-line.
In the next level(5), everything goes cool until you pass Atomic Number 39. Then you run into the 10 4d-transition elements. Then the reset of the level reverts to the main-line.
In the next level, everthing goes cool until you pass Barium. Then you run into the "rare-earths", 14 elements in which the 4f subshells are filled. This gets you to about element 71. Then, you have the 10 5d-transition elements. Then, you reach good-old Pb and fill out the 6p sub-shells.
On to the 7th level, the routine repeats again.
Elements 89-102 should be 5f analogs of the rare earths, followed by 10 elements where the 6-d transition is filling in, and then the rest of the 7th level, ending at Atomic Number 118, which is expected to be considerably more stable than most of the rest of the 7th level above #94.

Answer 2

the electron configuration element is very easy you must just memorize the ELECTRON DISTRIBUTION MNEMONICS it start on 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 7s 5f 6d 7p 6f 7d 7f note: s<2, p<6 , d<10, f<14. next know the atomic no. for example Uuo (Ununoctium) the atomic no is 118 the electron distribution is used to know the no. of electron is each subshell, the subshell is order as k l m n because during the days of democritus(the one who give the name atomos now called atoms) the alphabet strarts at k next distibute the electon for example krypton 36 the electon configutration of that is 1s2, 2s2, 2p2, 3s2, 3p2,4s2, 3d10,4p6, 5s2. the first no stands for the order of the subshell suck as 1=k, 2=l,3=m,4=n,5=o. the letter between the no. is the distributor, and the last no is the electron in eacjh subshell. just add the electron in each distributor to get the no. of electron in each subshell k=2, l=4, m=14,n=8,o=2.....