A compound with a percent compby mass of 87.5% N and 12.5% H. What is the empirical fo?

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a. NH2
b. N2H3
c. NH
d. N2H2
e. N2H

2007-10-13 15:47:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

Assume 100 g sample
N: 87.5 g / 14 g/mole = 6.25
H: 12.5 g / 1 g/mole = 12.5
NH2; ratio is 1 to 2 (6.25 : 12.5)
answer is a) NH2

2007-10-13 15:51:07 · answer #1 · answered by skipper 7 · 0⤊ 0⤋

NH2

87.5 / 14 (mass of N) = 6.25 mol N
12.5 / 1 (mass of H) = 12.5 mol H

6.25 / 6.25 = 1 N
12.5 / 6.25 = 2 H

empirical formula is N1H2 or NH2

2007-10-13 15:52:12 · answer #2 · answered by physandchemteach 7 · 0⤊ 0⤋