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I = E
------------
r + R
-----
N

or...

I = E/r+R/N

2007-10-13 15:43:00 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

ur all wrong its

-I*R/(I*r-E)

2007-10-13 16:49:44 · update #1

5 answers

[08]
I=E/r+R/N
R/N=I-E/r=(Ir-E)/r
N/R=r/(Ir-E)
N=Rr/(Ir-E)

2007-10-13 15:51:12 · answer #1 · answered by alpha 7 · 0 0

I'll presume this is what you mean...
I = E/[r + R/N]

Step 1: multiply both sides by [r + R/N]
(I)[r + R/N] = E

Step 2: distribute multiplication over addition on the left side...
Ir + IR/N = E

Step 3: Add - Ir tpo both sides...
IR/N = E - Ir

Step 4: Multiply both sides by N
IR = N(E - Ir)

Step 5: Multiply both sides by 1/(E - Ir)
and you have N=something...

2007-10-13 22:57:42 · answer #2 · answered by gugliamo00 7 · 0 0

not sure but is prolly start with bringing E/r to the other side:
(Ixr)/E=R/N
then cross multiply
N(Ixr)=RE
then divide both sides by Ixr to solve for N
so:
N=RE/Ir

2007-10-13 22:56:00 · answer #3 · answered by Michelle 2 · 0 0

I = E/r + R/N
I - E/r = R/N (subtract E/r from both sides)
N(I - E/r) = R (multiply both sides of equation by N, to get N out of the denominator)
N = R/(I - E/r) (divide both sides of equation by I - E/r)

2007-10-13 22:52:54 · answer #4 · answered by Sixer236 2 · 0 0

I = E/r + R/N
I - E/r = R/N
(Ir -E/r) = R/N
N(Ir - E/r) = R
N = R/(Ir - E/r)
N = Rr/(Ir^2 -E)

2007-10-13 22:51:28 · answer #5 · answered by Steve A 7 · 0 0

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