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Li + Cl2 --> LiCl

a) Given 10 grams of Chlorine determine grams of Lithium chloride.

first thing to do is balance the equation, right?

Li + Cl --> LiCl

to

2Li + Cl2 --> 2LiCl

2007-10-13 13:53:51 · 6 answers · asked by ashley 1 in Science & Mathematics Chemistry

6 answers

Then determine moles of chlorine, given 10 grams of chlorine gas. You'll have one mole of chlorine reacting with one mole of lithium, so you'll have X moles of chlorine becoming X moles of LiCl.

Finally, convert X moles of LiCl to grams of LiCl.

2007-10-13 14:01:01 · answer #1 · answered by Anonymous · 1 0

Change the 10 g Cl2 to moles Cl2.

10.0 g / 71 g per mole = 0.141 mol Cl2.

Look at your balance equation. You have a ratio of 2 LiCl to 1 Cl2. Multiply the number of moles Cl2 by "2" to get moles of LiCl used. Now multiply the number of moles LiCl (0.282 mol) by the mass of LiCl to get grams LiCl used.

2007-10-13 14:05:21 · answer #2 · answered by physandchemteach 7 · 1 0

Atomic weights: Li=6.9 Cl=35.5 Cl2=71 LiCl=42.4

10gCl2 x 1molCl2/71gCl2 x 2molLiCl/1molCl2 x 42.4gLiCl/1molLiCl = 12g lithium chloride, to two significant figures

2007-10-13 14:09:39 · answer #3 · answered by steve_geo1 7 · 1 0

convert grams of clorine to molesby dividing by the Molecular Mass (divide by 71g/mol) Multiple by the ratio of Cl2 to LiCl (1 mol Cl2 : 2 mol LiCl) to get moles of LiCl. Finally mulitply by the moles of LiCl by the Gram Formula Mass (multipy by 42.5g/mol)

2007-10-13 14:02:31 · answer #4 · answered by kentchemistry.com 7 · 1 0

You are correct, except for one thing. The 42.391 is grams per mole, so moles cancel and the final answer is in grams.

2016-05-22 07:22:14 · answer #5 · answered by ? 3 · 0 0

Put your hands in the air and back away from the Cain.

2007-10-13 14:03:49 · answer #6 · answered by yp_will_chicago_369 6 · 0 1

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