Find an equation of the line containing the given pair of points.?

Question

Find an equation of the line containing the given pair of points.

(-5, -8) and (-1, -2)

The equation of the line is y=

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Answer 1

(X-X1) / (Y-Y1)
-12/-3 = 4.

Answer 2

The formula to find the equation of a line, given two points that lie on that line is:

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)

So, let (-5,-8) be (x1, y1) and (-1,-2) be (x2, y2)

So, just substitute into the formula. You will get:

[y-(-8)] / [-2-(-8)] = [x-(-5)] / [-1-(-5)]
y+8 / 6 = x+5 / 4
4(y+8) = 6(x+5)
y+8 = 3/2 (x+5)
y+8 = 3/2 x +15/2
y = 3/2 x -1/2 (Ans)

Answer 3

Slope of the line = (-8+2)/(-5+1) = -6/-4=3/2

eq of line through (-1,-2) is (y + 2)/(x +1)= 3/2

y + 2 = 3/2(x + 1)
y = 3/2x + 3/2 - 2
y = 3/2x - 1/2

Answer 4

first find the slope= change in y cords/ change in x coords
= -8- ( -2)/ -5 - ( -1)
= -8+2/-5+1
=-6/-4
= +3/2


now use the point slope formula
y- ypoint = slope( x- xpoint)

I am going to use the first point but i culd use either and come to the same answer.
y-(-8) = 3/2( x - ( -5)
y+8 = 3/2( x+5)

y = 3/2( x+5) -8
you can foil that out and get your answer... 1 step to go

Answer 5

The above answer properly gives just the slope, or m in the form
y = mx + b.

Here is a web page that will get you both.

http://www.gomath.com/exercises/SlopeEquationYintercept.php