I need help simplifiying: 3x+6 divided by Xsquared - 4
PLEASE HELPPPP
Thank you in advance x :)
2007-10-13 11:11:00 · 7 answers · asked by x Animal Lover x 2 in Science & Mathematics ➔ Mathematics
Factor out things.
(3x+6)/(X^2-4)
(3(x+2))/((x+2)(x-2))
Then, remove what is common between the denominator and numerator.
3/(x-2), x cannot equal positive or negative two because the denominator cannot equal zero (look at the original equation).
2007-10-13 11:14:52 · answer #1 · answered by renomitsu 3 · 0⤊ 1⤋
Let's look at the original equation....
(3x+6)/(x^2 - 4)
Do you see anything? Do you think you can factor one side or the other? Actually, you can factor both sides....
(3(x+2)) /((x+2)(x-2))
Now, do you see a common term? If so eliminate it.
3/(x-2)
That's your answer, but let's go one step further. What happens if x is 2? Can you divide 3 by zero? No, correct? So you have a domain restriction. A complete answer is:
3/(x-2) where x is not equal to 2
2007-10-13 11:15:58 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
3x+6/xsquared-4 = xsquared +3x-3/2
2007-10-13 11:18:53 · answer #3 · answered by Mike 2 · 0⤊ 0⤋
This is actually pretty straightforward. The numerator (top half of the fraction) can have a 3 factored out of it. This turns it into 3*(x+2) .
The denominator (bottom half) is of the form (x^2)-(n^2). You may remember that this sort of thing factors into (x-n)*(x+n).
Therefore, your fraction can be written as (3*(x+2))/((x-2)*(x+2)) . You can then cancel out the (x+2) that appears in both the numerator and denominator, simplifying the fraction to your final answer:
3/(x-2)
Hope that helps!
-John
2007-10-13 11:23:28 · answer #4 · answered by hawk_stryke 2 · 0⤊ 0⤋
3/x-2 is the answer.
2007-10-13 11:15:16 · answer #5 · answered by Gabi ng Lagim 7 · 0⤊ 0⤋
since x^2-y^2=(x+y)(x-y)
so3x+6/(x^2-4)=3(x+2)/(x+2(x-2)=3/(x-2)
2007-10-13 11:42:50 · answer #6 · answered by rajini 2 · 0⤊ 0⤋
3x+6
=(3)-4+6
=-12+6
=-6
NEGATIVE 6!!!!!!
2007-10-13 11:15:05 · answer #7 · answered by J T 2 · 0⤊ 1⤋