5a + 6/ 2au - 3a + 6/ 2au???
2007-10-13 10:21:12 · 3 answers · asked by mariacruztexas 1 in Science & Mathematics ➔ Mathematics
5a +6/2au - 3a + 6/2au
= 2a + 6au
= 2a(3u+1)
2007-10-13 10:30:09 · answer #1 · answered by AJ B 2 · 0⤊ 0⤋
(5a + 6)/ (2au) - (3a + 6)/ (2au) <--I think you mean this.
= (5a+6-3a-6)/(2au)
=2a/(2au)
= 1/u
2007-10-13 10:31:00 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
one million. . . 15 . . .. 7 . . . 5 -------- + --- + ----- x(x+3) . . 8 . . x+3 uncomplicated denominators: . 8(15) . . 7x(x+3) . .. 8x(5) --------- + --------- + ---------- 8x(x+3) . 8x(x+3) .. 8x(x+3) a hundred and twenty + 7x² + 21x + 40x --------------------------- . . . . . . .8x(x+3) 7x² + 61x + a hundred and twenty ------------------- . . . 8x(x+3) (x+3)(7x+40) ---------------- . . 8x(x+3) 7x+40 -------- . . 8x it rather is none of your solutions. it ought to be divided out into (7/8) + (5/x), yet that may no longer considered one of your solutions the two. 2. 3/sixteen - 15/sixteen = -12/sixteen = -3/4 (selection d)
2016-12-14 16:52:49 · answer #3 · answered by barreda 4 · 0⤊ 0⤋