Please solve this equation for both variables "y" and "x". Anybody.?

Question

x(y^2)z = yx +xz + 1

Answer 1

x(y^2)z = yx +xz + 1
x [ y^2 z -y -z ] =1
x = 1/ (y^2 z -y -z)

y^2 xz - xy -xz -1 =0
y = ( -x +- sqrt( x^2 -4 (xz)( -xz+1) ) )/2xz

Answer 2

You won't get a number for an answer if that is what you want. However, you can separate the terms so that y or x is on one side and everything else is on the other. That is your solution.

For x; (y2)z*x-z*x-y*x= 1
So: (y2-y-z)*x=1 and x = 1/(y and z stuff)