English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

what happens to the open bonds that are created as neighboring sugar molecules lost component atoms during dehydraton synthesis?

2007-10-13 06:18:53 · 1 answers · asked by nicolehasacat 1 in Science & Mathematics Chemistry

1 answers

Let us take glucose for example. the glucose structure looks like -CH(OH)-CH(OH)-CH(OH)-. When it looses one water molecule, one OH group will be lost from one carton, and a H atom from the adjacent C. However, the H atom from the OH group attaching the second carbon would rearrange to the first carbon, so the final result would be either ketone or aldehyde:
-CH(OH)-CH(OH)-CH(OH)-
==> -CH=C(OH)-CH(OH)-
==> -CH2-C(=O)-CH(OH)-
Keeping doing that, finally the result would be just carbon black:
==> -C(triple bond to)C- ....

2007-10-13 07:46:23 · answer #1 · answered by Hahaha 7 · 0 0

fedest.com, questions and answers