Hi, please tell me what I'm doing wrong because I can't figure it out! I'm supposed to solve this trigonometric equation on [0, 2pi).
It is:
6cos²x + 5cosx + 1 = 0
I figured that I'd solve it with the quadratic, simple enough.
-5 +/- √(25 - (4)(6)(1)
------ --------- --------- --
12
=
-5 + 1
---------
12
and
-5-1
-------
12
Giving me -1/3 and -1/2. I then discarded the -1/3 (which I apparently shouldn't have), and got values of 7pi/6 and 11pi/6 for the -1/2.
What I'm thinking is that I should have used a calculator and done the arccos for both (-1/3) and (-1/2). Would that be the right thing to do?
Thanks so much for any help! I'll pick a best answer TODAY!!!!!
2007-10-13
05:29:12
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5 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Mathematics