Hepl me on a algebra word problem?

Question

Help me I can not do word problems at all
winter wheat- while finding the amount of seed needed to plant his three square wheat fields, Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field.. If the total area of the three fields is 38 square kilometers, then what is the area of each field

Answer 1

Let x = side of the smallest field.
The side of the largest field was x + 3.
The side of the remaining field was x + 1

The area of the three fields summed together is A =

x**2 + (x + 1)**2 + (x + 3 )**2 = x**2 + x**2 + 2x + 1 + x**2 + 6x + 9 = 3(x**2) + 8x + 10 = 38 or 3(x**2) + 8x - 28 = 0

Using the quadratic formula:
x =[ -8 +/- SQRT { 64 - 4(3)(-28) }]/6) = {-8 +/- SQRT ( 400)}/6
= ( -8 + 20)/6 = 2.

So, one field has an area of 4 sqkm, a second an area of 9 sqkm and the largest an area of 25 sqkm. ( these sum to 38, as specified ).

Answer 2

Since they are square fields you know that the area of each field is going to be length x width where length and width are the same number (because it's a square!) so that means the area of the large field will be (a squared). the area of the medium field will be (b squared) and the area of the small field will be (c squared). Now using the info you have you know a has to be 3 bigger than c and b has to be 1 bigger than c and added together they have to equal 38. So you just guess and test:
If c=1 and b=2 and a=4 you get:
1 squared =1
2 squared = 4
4 squared = 16; 1+4+16 = 21 so that doesn't work

Try this one -
2 squared =
3 squared =
5 squared =

:)

Answer 3

if we call the side of the largest field a (km) , the smallest field c (km) , and the side of the other field c (km) , we will have : a= c+3 , b= c+1 , because the total area of the three field is 38 square km : a^2+b^2+c^2=38
-->(c+3)^2+(c+1)^2+c^2=38 ---> c=2(suitable) of c= -14/3(not suitable )

Answer 4

Total area of the field equals 38 sq. m. divide it by 3 equals 12.6 sq. m./field