The graph of the function f(x) = 2e^x / 1 - 2e^x has which horizontal asymptotes?

0 ⤊

2007-10-12 17:40:12 · 2 answers · asked by mercin5 1 in Science & Mathematics ➔ Mathematics

when x is pos inf. f(x) -> -1 and x is -ve inf f(x) = 1

so horizontal asym is y=-1 and y=1

2007-10-12 17:49:34 · answer #1 · answered by norman 7 · 0⤊ 1⤋

You have two horizontal asymptotes:
y = -1 as x->â
y = 0 as x->-â

2007-10-12 18:05:25 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋