Let the function f be defined by f(x) = x2 - 7x + 10 and f(t + 1) = 0, what is one possible value of t?
Please explain. I don't understand why you can substitute in "t+1" for the "x" in the other equation.
2007-10-12 16:50:33 · 3 answers · asked by Snipe_AT 2 in Science & Mathematics ➔ Mathematics
x^2 - 7x + 10
Sorry didn't copy right.
2007-10-12 16:57:46 · update #1
I don't fully understand "god". What if the other equation said.
f(t+1) = 2?
2007-10-12 16:59:20 · update #2
You can substitute anything you want for the x in the function. That is the point of a function.
f(x)=x^2-7x+10
f(t+1)=(t+1)^2-7(t+1)+10
f(a)=a^2-7a+10
f(6)=6^2-7*6+10
etc.
2007-10-12 16:59:15 · answer #1 · answered by Amy W 6 · 0⤊ 0⤋
x^2 - 7x + 10 = (x-2)(x-5)
f(x) = 0 when x = 2 or 5
so t -1 = 2 or t - 1 = 5
t = 3 or 6
2007-10-12 16:55:35 · answer #2 · answered by norman 7 · 1⤊ 0⤋
x is a variable so there is no reason why you can't substitute (t+1) for x. If x can be any number or value, then the value t+1 is not restricted.
2007-10-12 16:55:51 · answer #3 · answered by god 2 · 0⤊ 0⤋