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what is the answer to -5.68 divided by (-0.02)? if u can please show steps thnks

2007-10-12 15:20:39 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

thanks for the help! =)

2007-10-12 15:42:40 · update #1

8 answers

-5.68 divided by (-0.02)

(-5.68)/(-0.002)
multiply the numerator by 1000/1000 to get
(-5.68*1000)/(-0.002*1000)=
-5680/(-2) = 2840

Note: dividing a negative number by a negative number we get a positive number

2007-10-12 15:23:30 · answer #1 · answered by Anonymous · 0 0

There are many ways to do this, here's one--

First, the minus signs will cancel, so you have 5.68 / 0.02
You could rewrite the numerator and denominator as fractions, so you get (568/100) / (2/100)
To divide a number by a fraction, invert the fraction and multiply, so (568/100) * (100/2).
Group the numerators and denominators together, so you get (568 * 100) / (100 * 2)
The 100 terms cancel, so you have 568 / 2
Simplifying, it's 284.

2007-10-12 22:30:16 · answer #2 · answered by gamblin man 6 · 0 0

5.68 divided by .02.
Forget the negative sign, as long as both are negative the answer is still positive so they don't matter.

The easiest way is to multiply both numbers by 100 so that you get rid of the decimals.
So now you have 568/2, which is 284.

2007-10-12 22:43:39 · answer #3 · answered by Anonymous · 0 0

-5.68/-.02=284
move decimal place over 2 places and the problem becomes 568/2 and -/-=+

2007-10-12 22:30:55 · answer #4 · answered by waterraven2 2 · 0 0

284

2007-10-12 22:27:07 · answer #5 · answered by john 4 · 0 0

284
move the decimals two spaces and divide
284
02 568
4
---------------
16
16
---------------
8
8
-------------------
0

Because they are both negative numbers, the negatives cancel each other out and the answer is a positive number.
Hope this helps

2007-10-12 22:35:38 · answer #6 · answered by Dana O 3 · 0 0

-5.68/-0.02=5.68/0.02=568/2=284

2007-10-12 22:27:34 · answer #7 · answered by rajini 2 · 0 0

568
---- = 284
2

2007-10-13 12:49:46 · answer #8 · answered by Como 7 · 0 0

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