Can someone help me solve this equation?

Question

Ok this is an equation used for some type of distance.Acceleration, distance traveled, velocity, and time are related in the formula d=vt+1/2at^2.
Solve for a and justify each step.

just confused how to begin.
thanks.=]

Thanks Clarie, it makes sense now.
it was so simple.XD

Answer 1

d = v t + (1/2) a t ²
2 d = 2 v t + a t ²
a t ² = 2 d - 2 v t
a = 2 ( d - v t ) / t ²

Answer 2

solve for what? it would be easier if you gave a word problem... if you want to know how the formula got that way, it's another story... i'll need time to remember things.

the formula for distance is
d=vt that is if the velocity is constant
when the object is accelerating, you just add +1/2at^2

oh i didnt read the details correctly... anywho..

solving for acceleration=a

1. d=vt+1/2at^2.
2. d-vt=1/2at^2
3. 2(d-vt)=at^2
4. 2(d-vt)/t^2 =a

done

Answer 3

d=vt+1/2at^2.
1/2at^2 = d - vt
at^2 = 2(d - vt)
a = (2d - 2vt)/t^2

Answer 4

d=vt+1/2at^2.

(d-vt )= 1/2 (a)(t^2)
a = 2(d-vt)/(t^2)