math/chemistry problem?

Question

Silver, being one of the best conductors of electricity, is used in the electrical wiring for high-end stereo equipment. What would the temperature be of a 0.325 kg silver conductor that has been carrying a current for two hours? The specific heat of silver is 0.23 J/g C, the wiring is at a temperature of 23° C and it absorbs 3.45x103 J of energy.

A 5.00 g calorimeter, c=15.77 J/g °C, is used to measure the heat capacity of an unknown metal. The 8.60 g unknown metal is first placed in a boiling water bath for several minutes then placed in the calorimeter. The calorimeter has 151 g of 23° C water in it. If the final temperature of both the metal and the water is 52° C, calculate the heat capacity of the metal.

How would you work these two problems?

Answer 1

Problem 1:
(3.45x10^3 J) /(325 g*0.23 J/g °C) = 46°C
The final temperature of this wire is 46°C + 23°C = 69°C.

Problem 2:
We know the heat capacity of water to be 4.182J/g °C
Let the heat capacity of the metal to be X(J/g °C).
8.60*(100-52)*X = (5.00*15.77 + 151*4.18)*(52 - 23)
X = 50 (J/g °C).
I never know a metal to have such a high heat capacity, though.